0=8x^2-3x-5

Solution for 0=8x^2-3x-5 equation:

0=8x^2-3x-5

We move all terms to the left:

0-(8x^2-3x-5)=0

We add all the numbers together, and all the variables

-(8x^2-3x-5)=0

We get rid of parentheses

-8x^2+3x+5=0

a = -8; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-8)·5
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*-8}=\frac{-16}{-16}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*-8}=\frac{10}{-16}
=-5/8
$